document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26064>Question 26064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WE HAVE 5ML OF 80% ACID WE NEED TO DILUTE IT WITH 2% ACID TO GET 10%. HOW MUCH 2%DO WE NEED?\r<BR>\n" );
document.write( "\n" );
document.write( "MARILYN WANTS TO COMBINE A 30% ALCOHOL SOLUTION WITH 50% ALCOHOL SOLUTION TO GET 500MG OF AN 80% ALCOHOL SOLUTION PLEASES HELP HER ACCOMPLISH THIS TASK? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13996 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13996\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.<BR>\n" );
document.write( "80(5)+2x=10(x+5)<BR>\n" );
document.write( "400+2x=10x+50<BR>\n" );
document.write( "-8x=-350<BR>\n" );
document.write( "x=43.75\r<BR>\n" );
document.write( "\n" );
document.write( "Hence, about 43.75ml of sloution is needd.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2.80(500)-30x=50(500+x)<BR>\n" );
document.write( "40000-30x=50x+25000<BR>\n" );
document.write( "-80x=-15000<BR>\n" );
document.write( "x=187.5<BR>\n" );
document.write( "500-187.5 = 312.5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hence, about 187.5mg of 30% is needed and about 312.5mg of 50% is needed.<BR>\n" );
document.write( "Paul.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );