document.write( "Question 186539: Solve the system.
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document.write( "2x+2y+3z=10
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document.write( "3x+y-z=0
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document.write( "x+y+2z=6\r
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document.write( "x=
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document.write( "y=
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document.write( "z= \n" );
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Algebra.Com's Answer #139959 by uday1435(57)![]() ![]() You can put this solution on YOUR website! 2x+2y+3z=10 (1) \n" ); document.write( "3x+y-z=0 (2) \n" ); document.write( "x+y+2z=6 (3)\r \n" ); document.write( "\n" ); document.write( "Multiply eqn (2) by 2 and subtract from eqn(1) \n" ); document.write( "2x+2y+3z=10 (1) \n" ); document.write( "6x+2y - 2z=0 (2) x 2\r \n" ); document.write( "\n" ); document.write( "- 4x + 5z = 10 (4) (1) – (2) x 2 \n" ); document.write( "Multiply eqn (3) by 2 and subtract from eqn(1)\r \n" ); document.write( "\n" ); document.write( "2x+2y+3z=10 (1) \n" ); document.write( "2x+2y+4z=12 (5) (3) x 2\r \n" ); document.write( "\n" ); document.write( "- z = - 2 \n" ); document.write( "So z = 2 \n" ); document.write( "Plugging in the value of z in eqn(4) \n" ); document.write( "- 4x + 5(2) = 10; -4x = 10-10 =0; so x = 0 \n" ); document.write( "Now plug-in the values of x (=0) ad z (=2) in eqn (3)\r \n" ); document.write( "\n" ); document.write( "x + y + 2z = 6 (3) \n" ); document.write( "0 + y +2(2) =6 \n" ); document.write( "y + 4 =6; so y = 6-4 = 2\r \n" ); document.write( "\n" ); document.write( "So the answers are x =0, y=2, z = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need further clarification, please email: udayakumar.t.r@gmail.com \n" ); document.write( " \n" ); document.write( " |