document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186697>Question 186697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorcycle traveling 60mph overtakes a police patrol car traveling at 40mph that had a 3hr head start. How far from the starting point are the two vehicles?<BR>\n" );
document.write( "a) 360miles b) 279 miles c) 187 miles d) 290 miles<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139955 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the police car has a 3hr headstart, and is moving at 40 mph, he is 3 x 40 = 120 miles ahead of the motorcycle. To catch up this gap he has a relative speed of (60-40 = 20mph). <BR>\n" );
document.write( "So the time needed to catch up = distance/speed = 120/20 = 6 hours.<BR>\n" );
document.write( "In that time he has to travel a distance = speed x time = 60 x 6 = 360 miles\r<BR>\n" );
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document.write( "Amswer:  360 miles\r<BR>\n" );
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document.write( "If you still need further clarifications please contact udayakumar.t.r@gmail.com </SPAN>\n" );
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