document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26064>Question 26064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WE HAVE 5ML OF 80% ACID WE NEED TO DILUTE IT WITH 2% ACID TO GET 10%. HOW MUCH 2%DO WE NEED?\r<BR>\n" );
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document.write( "MARILYN WANTS TO COMBINE A 30% ALCOHOL SOLUTION WITH 50% ALCOHOL SOLUTION TO GET 500MG OF AN 80% ALCOHOL SOLUTION PLEASES HELP HER ACCOMPLISH THIS TASK? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13995 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> #1. Follow the acid.<BR>\n" );
document.write( "Start with 80%(5)<BR>\n" );
document.write( "Add 2%(x);  x because the amount of fluid added is unknown<BR>\n" );
document.write( "End up with: 10%(5+x)<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "  80%(5)+2%(x)=10%(5+x)<BR>\n" );
document.write( "Multiply through by 100 to get:<BR>\n" );
document.write( "  80(5)+2x=10(5+x)<BR>\n" );
document.write( "  400+2x=50+10x<BR>\n" );
document.write( "     8x=350<BR>\n" );
document.write( "      x= 43.75ml (amount of 2% fluid you need to add)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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