document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186686>Question 186686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve each system. substitute a for 1/x and b for 1/y. solve for a and b, then find x and y\r<BR>\n" );
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document.write( "1/x+2/y=-1<BR>\n" );
document.write( "2/x-1/y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139949 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/x+2/y=-1<BR>\n" );
document.write( "2/x-1/y=-7\r<BR>\n" );
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document.write( "Substitutig  a = 1/x and b =1/y we get\r<BR>\n" );
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document.write( "a + 2b = - 1			Eq(1)<BR>\n" );
document.write( "2a – b = - 7			Eq(2) . \r<BR>\n" );
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document.write( "Multiply Eq(1) by 2 and subtract from Eq.(2) we get\r<BR>\n" );
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document.write( "2a – b = - 7				Eq(2) . <BR>\n" );
document.write( "2a + 4b = - 2			Multiplied Eq(1)  by  2 \r<BR>\n" );
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document.write( "	- 5b = - 5			subtractig the above eqs<BR>\n" );
document.write( "	 b = (- 5/- 5) = 1<BR>\n" );
document.write( "Pluging in the value of  b in Eq(1) we have\r<BR>\n" );
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document.write( "a + 2(1) = -1 ;  a = - 1 – (2) = - 3; so x =1/a = 1/(-3)  = - 1/3 and y = 1/b = 1/1 =1<BR>\n" );
document.write( "Hence the solution is a = - 1/3 and b = 1<BR>\n" );
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