document.write( "Question 186673: sara and Bill live 13.5 miles apart . AT 10:00 AM they both leave their houses and start walking toward one another. THe ratio of Sara's speed to Bill's speed is 5:4. If they meet at 11:45 , how fast were they walking. Thanks \n" ); document.write( "
Algebra.Com's Answer #139947 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! sara and Bill live 13.5 miles apart . AT 10:00 AM they both leave their houses and start walking toward one another. THe ratio of Sara's speed to Bill's speed is 5:4. If they meet at 11:45 , how fast were they walking. \n" ); document.write( ": \n" ); document.write( "Let x = the multiplier of their speed \n" ); document.write( "5x = Bill's speed \n" ); document.write( "4x = Sara's speed \n" ); document.write( ": \n" ); document.write( "Their walking time 1.75 hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation: dist = time * speed \n" ); document.write( "B's dist + S's dist = 13.5 mi \n" ); document.write( "1.75(5x) + 1.75(4x) = 13.5 \n" ); document.write( "8.75x + 7x = 13.5 \n" ); document.write( "15.75x = 13.5 \n" ); document.write( "x = \n" ); document.write( "B's speed = 5* \n" ); document.write( "S's speed = 4* \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Check solution by find the total distance \n" ); document.write( "1.75*4.2857 = 7.5 mi \n" ); document.write( "1.75*3.4286 = 6 mi \n" ); document.write( "-------------------- \n" ); document.write( "total dist = 13.5 mi \n" ); document.write( " |