document.write( "Question 186673: sara and Bill live 13.5 miles apart . AT 10:00 AM they both leave their houses and start walking toward one another. THe ratio of Sara's speed to Bill's speed is 5:4. If they meet at 11:45 , how fast were they walking. Thanks \n" ); document.write( "
Algebra.Com's Answer #139947 by ankor@dixie-net.com(22740)\"\" \"About 
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sara and Bill live 13.5 miles apart . AT 10:00 AM they both leave their houses and start walking toward one another. THe ratio of Sara's speed to Bill's speed is 5:4. If they meet at 11:45 , how fast were they walking.
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\n" ); document.write( "Let x = the multiplier of their speed
\n" ); document.write( "5x = Bill's speed
\n" ); document.write( "4x = Sara's speed
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\n" ); document.write( "Their walking time 1.75 hrs
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\n" ); document.write( "Write a distance equation: dist = time * speed
\n" ); document.write( "B's dist + S's dist = 13.5 mi
\n" ); document.write( "1.75(5x) + 1.75(4x) = 13.5
\n" ); document.write( "8.75x + 7x = 13.5
\n" ); document.write( "15.75x = 13.5
\n" ); document.write( "x = \"13.5%2F15.75\"
\n" ); document.write( "B's speed = 5*\"13.5%2F15.75\" = 4.2857 mph
\n" ); document.write( "S's speed = 4*\"13.5%2F15.75\" = 3.4286 mph
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\n" ); document.write( "Check solution by find the total distance
\n" ); document.write( "1.75*4.2857 = 7.5 mi
\n" ); document.write( "1.75*3.4286 = 6 mi
\n" ); document.write( "--------------------
\n" ); document.write( "total dist = 13.5 mi
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