document.write( "Question 186688: 1+3/x=5/x^2 \n" ); document.write( "
Algebra.Com's Answer #139946 by jim_thompson5910(35256)\"\" \"About 
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\"1%2B3%2Fx=5%2Fx%5E2\" Start with the given equation. \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x=5\" Multiply EVERY term by the LCD \"x%5E2\" to clear out the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x-5=0\" Subtract 5 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=1\", \"b=3\", and \"c=-5\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%281%29%28-5%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=3\", and \"c=-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9-4%281%29%28-5%29+%29%29%2F%282%281%29%29\" Square \"3\" to get \"9\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9--20+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-5%29\" to get \"-20\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9%2B20+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%289--20%29\" as \"sqrt%289%2B20%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+29+%29%29%2F%282%281%29%29\" Add \"9\" to \"20\" to get \"29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+29+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2Bsqrt%2829%29%29%2F%282%29\" or \"x+=+%28-3-sqrt%2829%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+%28-3%2Bsqrt%2829%29%29%2F%282%29\" or \"x+=+%28-3-sqrt%2829%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=1.193\" or \"x=-4.193\"
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