document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26051>Question 26051</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I would like to know if someone can help me figure out how to do this type of problem. I'm not so much concerned with getting answers, more I need to understand how to do it myself. Thanks :o)\r<BR>\n" );
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document.write( "Solve the system of equations using the substitution method.<BR>\n" );
document.write( "3x + y = 2<BR>\n" );
document.write( "2x – y = 3\r<BR>\n" );
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document.write( "Solve the system of equations using the addition (elimination) method.<BR>\n" );
document.write( "3x – 11y = 9<BR>\n" );
document.write( "-9x + 33y = 18<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13994 by </B><A HREF=/tutors/aboutme.mpl?userid=Ashley1516><B>Ashley1516(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ashley1516><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hey, <BR>\n" );
document.write( "I can help u with the first problem but I'm not sure about the second one.<BR>\n" );
document.write( "OK...First, you need to either get the y or the x by itself, with this problem it's easier to get the y in equation 1. Since 3x is positive, subtract it from both sides of the eq. (from itself & 2). Like so:<BR>\n" );
document.write( "3x+y=2(eq.1)<BR>\n" );
document.write( "-3x -3x<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Switch it around:<BR>\n" );
document.write( "y=-3x+2 Ah Ha! Now u know what y equals, so u can SUBSTITUTE it into eq.2!\r<BR>\n" );
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document.write( "2x-y=3(eq.2)<BR>\n" );
document.write( "2x-(-3x+2)=3 Solve this:  <BR>\n" );
document.write( "2x+3x-2=3 Add the two likes together(x's):<BR>\n" );
document.write( "5x-2=3 Add 2 to both sides of the eq.:<BR>\n" );
document.write( "  +2+2<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "5x=5 Divide by 5:<BR>\n" );
document.write( "*x=1* Ok...U have the x, now just find the y by useing SUBSTITUTION again!<BR>\n" );
document.write( "Plug the x into eq.1:<BR>\n" );
document.write( "3(1)+y=2 Now solve:<BR>\n" );
document.write( "3+y=2 Subtract 3 from both sides:<BR>\n" );
document.write( "-3 -3<BR>\n" );
document.write( "------<BR>\n" );
document.write( "*y=-1* You've got y!<BR>\n" );
document.write( "NOW, YOUR ANSWER IS(x,y):<BR>\n" );
document.write( "*(1,-1)*\r<BR>\n" );
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document.write( "How to CHECK your answer,<BR>\n" );
document.write( "Plug in the x & y into both equations:<BR>\n" );
document.write( "3x+y=2<BR>\n" );
document.write( "3(1)=-1=2<BR>\n" );
document.write( "3=-1=2<BR>\n" );
document.write( "2=2 CORRECT!\r<BR>\n" );
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document.write( "2x-y=3<BR>\n" );
document.write( "2(1)-(-1)=2<BR>\n" );
document.write( "2-(-1)=3<BR>\n" );
document.write( "3=3 CORRECT!\r<BR>\n" );
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document.write( "I REALLY hope this helps!<BR>\n" );
document.write( "~aShLeY~\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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