document.write( "Question 186620: Wite the slope-intercept form of an equation for a line that passes through (-1,0) and is perpendicular to the graph of 3x-5y=20 \n" ); document.write( "
Algebra.Com's Answer #139902 by uday1435(57)\"\" \"About 
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The given line is 3x – 5y = 20 ; adding 5y – 20 on both sides we get\r
\n" ); document.write( "\n" ); document.write( "3x – 5y + 5y – 20 = 20 + 5y – 20
\n" ); document.write( "3x – 20 = 5y. interchanging the sides we get
\n" ); document.write( "5y = 3x – 20 Dividing both sides by 5 we get
\n" ); document.write( "y = (3x – 20)/5 = (3/5) x – 4 comparing with y = mx + b we have (3/5) as m\r
\n" ); document.write( "\n" ); document.write( "means the slope of this line is 3/5 . A line perpendicular to this line must have its slops as the negative reciprocal of this line. So the slope of the new line = - (5/3) . Let the new line be
\n" ); document.write( "y = (-5/3) x + b ----- equation 1
\n" ); document.write( "Given that the new line passes through ( - 1, 0) . so when its x = -1, y =0 . Let us plug-in these values into equation 1
\n" ); document.write( "0 = (-5/3) (-1) + b
\n" ); document.write( "That is 0 = (5/3) + b
\n" ); document.write( "That is b = ( - 5/3)
\n" ); document.write( "Pluging in the value of b in equation 1 we get y = - ( 5/3) x - (5/3)
\n" ); document.write( "Which is the required equation
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