document.write( "Question 186620: Wite the slope-intercept form of an equation for a line that passes through (-1,0) and is perpendicular to the graph of 3x-5y=20 \n" ); document.write( "
Algebra.Com's Answer #139899 by nerdybill(7384)\"\" \"About 
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Wite the slope-intercept form of an equation for a line that passes through (-1,0) and is perpendicular to the graph of 3x-5y=20
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\n" ); document.write( "First, determine the slope of
\n" ); document.write( "3x-5y=20
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\n" ); document.write( "Do this by putting it into the \"slope-intercept\" form:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where
\n" ); document.write( "m is slope
\n" ); document.write( "b is y-intercept
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\n" ); document.write( "3x-5y=20
\n" ); document.write( "-5y = 3x + 20
\n" ); document.write( "y = (-3/5)x + (-3/5)20
\n" ); document.write( "y = (-3/5)x - 12
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\n" ); document.write( "So, if we want to be \"perpendicular\" to the line above, the NEW slope must be the \"negative reciprocal\" of -3/5.
\n" ); document.write( "Let M = our new slope
\n" ); document.write( "M(-3/5) = -1
\n" ); document.write( "M = 5/3
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\n" ); document.write( "The NEW line now has
\n" ); document.write( "slope of 5/3
\n" ); document.write( "passing through (-1,0)
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\n" ); document.write( "Plug the above into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 0 = (5/3)(x - (-1))
\n" ); document.write( "y = (5/3)(x + 1)
\n" ); document.write( "y = (5/3)x + 5/3 (this is what they're asking for)\r
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