document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186609>Question 186609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a company makes both LCD and CRT color monitors. the cost of materials for a CRT monitor is $50, whereas the cost of materials for a LCD monitor is $150. cost of labor to make a CRT monitor is $80, whereas the cost of labor to make an LCD monitor is $130. during a week when the company has budgeted $9600 for materials and $8760 for labor, how many LCD monitors does the company plan to make? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139878 by </B><A HREF=/tutors/aboutme.mpl?userid=dukesmart><B>dukesmart(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dukesmart><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let  put x= CRT plan to be made<BR>\n" );
document.write( "         y= LCD plan to be made<BR>\n" );
document.write( "we create the equations as follows:\r<BR>\n" );
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document.write( "50x+150y= 9600 ......(1)<BR>\n" );
document.write( "80x+130y= 8760 ......(2)\r<BR>\n" );
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document.write( "equation (1) can be multiply by 8/5 will become; 80x + 240y = 15360 ...(3)<BR>\n" );
document.write( "let take (3) subtract (2) we will have: 240y-130y=15360-8760<BR>\n" );
document.write( "                                   or:       110y= 6600 then y=60<BR>\n" );
document.write( "plan to make 60 LCD and 12 CRT. </SPAN>\n" );
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