document.write( "Question 186599: w^2-12w+20 \n" ); document.write( "
Algebra.Com's Answer #139861 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"w%5E2-12w%2B20\", we can see that the first coefficient is \"1\", the second coefficient is \"-12\", and the last term is \"20\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"20\" to get \"%281%29%2820%29=20\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"20\" (the previous product) and add to the second coefficient \"-12\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"20\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"20\":\r
\n" ); document.write( "\n" ); document.write( "1,2,4,5,10,20\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-5,-10,-20\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"20\".\r
\n" ); document.write( "\n" ); document.write( "1*20
\n" ); document.write( "2*10
\n" ); document.write( "4*5
\n" ); document.write( "(-1)*(-20)
\n" ); document.write( "(-2)*(-10)
\n" ); document.write( "(-4)*(-5)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-12\":\r
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First NumberSecond NumberSum
1201+20=21
2102+10=12
454+5=9
-1-20-1+(-20)=-21
-2-10-2+(-10)=-12
-4-5-4+(-5)=-9
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-2\" and \"-10\" add to \"-12\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-2\" and \"-10\" both multiply to \"20\" and add to \"-12\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-12w\" with \"-2w-10w\". Remember, \"-2\" and \"-10\" add to \"-12\". So this shows us that \"-2w-10w=-12w\".\r
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\n" ); document.write( "\n" ); document.write( "\"w%5E2%2Bhighlight%28-2w-10w%29%2B20\" Replace the second term \"-12w\" with \"-2w-10w\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28w%5E2-2w%29%2B%28-10w%2B20%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"w%28w-2%29%2B%28-10w%2B20%29\" Factor out the GCF \"w\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"w%28w-2%29-10%28w-2%29\" Factor out \"10\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28w-10%29%28w-2%29\" Combine like terms. Or factor out the common term \"w-2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"w%5E2-12w%2B20\" factors to \"%28w-10%29%28w-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing \"%28w-10%29%28w-2%29\" to get \"w%5E2-12w%2B20\" or by graphing the original expression and the answer (the two graphs should be identical).
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