document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26050>Question 26050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me understand how to solve this problem:<BR>\n" );
document.write( "11-2x=x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13986 by </B><A HREF=/tutors/aboutme.mpl?userid=CasaNova><B>CasaNova(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CasaNova><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first, what you do is send variables to one side and #s on the other. So,for example you put -2x on the x+2 side. Then that becomes 3x+2=11. Then what you do is you subtract 2 to both sides of the equation which turns out 3x=9. the last thing you do is divide both sides by three( to get the x by itself). your answer should be x=3! </SPAN>\n" );
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