document.write( "Question 186596: log3 + 2 = log x\r
\n" ); document.write( "\n" ); document.write( "solve for x\r
\n" ); document.write( "\n" ); document.write( "logs are to base 10
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Algebra.Com's Answer #139858 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log3 + 2 = log x
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\n" ); document.write( "log(x) - log(3) = 2\r
\n" ); document.write( "\n" ); document.write( "log(x/3) = 2\r
\n" ); document.write( "\n" ); document.write( "x/3 = 10^2\r
\n" ); document.write( "\n" ); document.write( "x/3 = 100\r
\n" ); document.write( "\n" ); document.write( "x = 300
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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