document.write( "Question 186597: Hi guys, im stumped with this one:\r
\n" ); document.write( "\n" ); document.write( "2ln2 - ln(x-1) = ln(2x)\r
\n" ); document.write( "\n" ); document.write( "solve for 'x'.\r
\n" ); document.write( "\n" ); document.write( "cheers =) \n" ); document.write( "
Algebra.Com's Answer #139857 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
You will need to apply \"log rules\".
\n" ); document.write( "Review them at:
\n" ); document.write( "http://www.purplemath.com/modules/logrules.htm
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\n" ); document.write( "2ln2 - ln(x-1) = ln(2x)
\n" ); document.write( "2ln(2/(x-1)) = ln(2x)
\n" ); document.write( "ln(2/(x-1))^2 = ln(2x)
\n" ); document.write( "(2/(x-1))^2 = 2x
\n" ); document.write( "2^2/(x-1)^2 = 2x
\n" ); document.write( "4/(x-1)^2 = 2x
\n" ); document.write( "2/(x-1)^2 = x
\n" ); document.write( "2 = x(x-1)^2
\n" ); document.write( "2 = x(x-1)(x-1)
\n" ); document.write( "2 = x(x^2-x-x+1)
\n" ); document.write( "2 = x(x^2-2x+1)
\n" ); document.write( "2 = x^3-2x^2+x
\n" ); document.write( "0 = x^3-2x^2+x-2
\n" ); document.write( "Factor (by grouping) on the right:
\n" ); document.write( "0 = (x^3-2x^2)+(x-2)
\n" ); document.write( "0 = x^2(x-2)+(x-2)
\n" ); document.write( "0 = (x-2)(x^2+1)
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\n" ); document.write( "Setting each term (in parenthesis to zero) we get:
\n" ); document.write( "x = {2, i}\r
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