document.write( "Question 185958: use the empirical rule to estimate the area lying between values x=1100 and x=2600 under the normal curve that has mean 2100 and standard deviation 500. do not use calculator \n" ); document.write( "
Algebra.Com's Answer #139831 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! use the empirical rule to estimate the area lying between values x=1100 and x=2600 under the normal curve that has mean 2100 and standard deviation 500. do not use calculator \n" ); document.write( "------------------------- \n" ); document.write( "z(1100) = (1100-2100)/500 = 2 \n" ); document.write( "z(2600) = (2600-2100)/500 = 1 \n" ); document.write( "-------------------------------- \n" ); document.write( "The area from z=0 to z=2 is (1/2)95% = 47.5% \n" ); document.write( "The area from z=0 to z=1 is (1/2)68% = 34% \n" ); document.write( "---------------------------- \n" ); document.write( "So, the area from z=1 to z=2 is 47.5%-34% = 13.5% \n" ); document.write( "====================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |