document.write( "Question 186557This question is from textbook
\n" ); document.write( ": A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate?
\n" ); document.write( " D = R x T
\n" ); document.write( "bike 12 mi r+10 5 hr
\n" ); document.write( "hike 8 mi r 5 hr\r
\n" ); document.write( "\n" ); document.write( "Am i on the right track?
\n" ); document.write( "

Algebra.Com's Answer #139813 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate?
\n" ); document.write( "-------------------------------
\n" ); document.write( "Walking DATA:
\n" ); document.write( "distance = 8 miles ; rate = x mph ; time = 8/x hrs.
\n" ); document.write( "-------------------------
\n" ); document.write( "Biking DATA:
\n" ); document.write( "distance = 12 miles : rate = (x+10)mph ; time = 12/(x+10) hrs
\n" ); document.write( "--------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "8/x + 12/(x+10) = 5
\n" ); document.write( "----
\n" ); document.write( "Multiply thru by x(x+10) you get:
\n" ); document.write( "8(x+10) + 12x = 5x(x+10)
\n" ); document.write( "8x + 80 + 12x = 5x^2 + 50x
\n" ); document.write( "5x^2 + 30x - 80 = 0
\n" ); document.write( "x^2 + 6x - 16 = 0
\n" ); document.write( "(x+8)(x-2) = 0
\n" ); document.write( "---
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 2 mph (walking rate)
\n" ); document.write( "x+10 = 12 mph (bicycling rate)
\n" ); document.write( "==================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );