document.write( "Question 186557This question is from textbook
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document.write( ": A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate?
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document.write( " D = R x T
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document.write( "bike 12 mi r+10 5 hr
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document.write( "hike 8 mi r 5 hr\r
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document.write( "Am i on the right track? \n" );
document.write( "
Algebra.Com's Answer #139813 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate? \n" ); document.write( "------------------------------- \n" ); document.write( "Walking DATA: \n" ); document.write( "distance = 8 miles ; rate = x mph ; time = 8/x hrs. \n" ); document.write( "------------------------- \n" ); document.write( "Biking DATA: \n" ); document.write( "distance = 12 miles : rate = (x+10)mph ; time = 12/(x+10) hrs \n" ); document.write( "-------------------------- \n" ); document.write( "Equation: \n" ); document.write( "8/x + 12/(x+10) = 5 \n" ); document.write( "---- \n" ); document.write( "Multiply thru by x(x+10) you get: \n" ); document.write( "8(x+10) + 12x = 5x(x+10) \n" ); document.write( "8x + 80 + 12x = 5x^2 + 50x \n" ); document.write( "5x^2 + 30x - 80 = 0 \n" ); document.write( "x^2 + 6x - 16 = 0 \n" ); document.write( "(x+8)(x-2) = 0 \n" ); document.write( "--- \n" ); document.write( "Positive solution: \n" ); document.write( "x = 2 mph (walking rate) \n" ); document.write( "x+10 = 12 mph (bicycling rate) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |