document.write( "Question 186554This question is from textbook
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document.write( ": the length of a fence required to enclose a rectangular field is 3000 meters. what are the dimensions of the field if it is known that the difference between the length and width is 50 meters? \n" );
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Algebra.Com's Answer #139802 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+50 \n" ); document.write( "2L+2W=3000 \n" ); document.write( "2(W+50)+2W=3,000 \n" ); document.write( "2W+100+2W=3,000 \n" ); document.write( "4W=3000-100 \n" ); document.write( "4W=2,900 \n" ); document.write( "W=2,900/4 \n" ); document.write( "W=725 M. IS THE WIDTH OF THE FIELD. \n" ); document.write( "L=725+50=775 M. IS THE LENGTH OF THE FIELD. \n" ); document.write( "PROOF: \n" ); document.write( "2*725+2*775=3,000 \n" ); document.write( "1450+1,550=3,000 \n" ); document.write( "3,000=3,000 \n" ); document.write( " |