document.write( "Question 186542: Solve the System.\r
\n" ); document.write( "\n" ); document.write( "2x+3y+2z=1
\n" ); document.write( "2x-3y+2z=-1
\n" ); document.write( "4x+3y-2z=4\r
\n" ); document.write( "\n" ); document.write( "x=
\n" ); document.write( "y=
\n" ); document.write( "z=
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Algebra.Com's Answer #139798 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
2x + 3y + 2z = 1
\n" ); document.write( "2x - 3y + 2z =-1
\n" ); document.write( "4x + 3y - 2z = 4
\n" ); document.write( ":
\n" ); document.write( "Use elimination with subtraction on 1st two equations
\n" ); document.write( "2x + 3y + 2z = 1
\n" ); document.write( "2x - 3y + 2z =-1
\n" ); document.write( "------------------
\n" ); document.write( "0x + 6y + 0z = 2
\n" ); document.write( "6y = 2
\n" ); document.write( "y = \"2%2F6\" = \"1%2F3\"
\n" ); document.write( ":
\n" ); document.write( "Add the last two equations, eliminate y & z, find x
\n" ); document.write( "2x - 3y + 2z =-1
\n" ); document.write( "4x + 3y - 2z = 4
\n" ); document.write( "------------------
\n" ); document.write( "6x + 0y + 0z = 3
\n" ); document.write( "6x = 3
\n" ); document.write( "x = \"3%2F6\" = \"1%2F2\"
\n" ); document.write( ":
\n" ); document.write( "Using the 1st equation, substitute for x & y, to find z
\n" ); document.write( "2(\"1%2F2\") + 3(\"1%2F3\") + 2z = 1
\n" ); document.write( "1 + 1 + 2z = 1
\n" ); document.write( "2z = 1 - 2
\n" ); document.write( "z = \"-1%2F2\"
\n" ); document.write( ";
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\n" ); document.write( "You can check the solutions in the 2nd and 3rd equation
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