document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186475>Question 186475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a farmer has 500 feet of fencing with which to build a rectangluar live stock pen and wants to enclose the maximum area. okay here is my prob i know how to get the maximum area but it also says to show a graph of the possibilties and i am stuck i did get help with and understand how to use varibles  but i'm just not sure how i get this graphed is ther some fabulous trick i don't know about??i am struggling with this last math project and totally bombed on the last one i just need a few pointers on what to do thank you all so very much <BR>\n" );
document.write( "tanya </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139769 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width of the pen.\r<BR>\n" );
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document.write( "If you have 500 feet of fence, then this is the perimeter, so<BR>\n" );
document.write( "2W + 2L = 500\r<BR>\n" );
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document.write( "You need to find the length L in terms of x, remembering that x= width.<BR>\n" );
document.write( "2x + 2L = 500  You have to solve for L.\r<BR>\n" );
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document.write( "Divide both sides by 2 to simplify things a bit:<BR>\n" );
document.write( "x + L = 250\r<BR>\n" );
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document.write( "Subtract x from each side<BR>\n" );
document.write( "L=250-x\r<BR>\n" );
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document.write( "So, now you have a formula for Area in terms of x:\r<BR>\n" );
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document.write( "A=W*L<BR>\n" );
document.write( "A= x*(250-x)\r<BR>\n" );
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document.write( "Graph y=x*(250-x)\r<BR>\n" );
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document.write( "To find the maximum area, you can graph this equation.  I recommend that you graph this from x=0 to about x=250.  It can't go past these values for x, right?\r<BR>\n" );
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document.write( "Now, (did you say that you know what the maximum is?  It's a square, so each side will be 500/4 = 125, and the area will be 125^2 = 15625!!)  graph y values from y=0 up to about 16000.  The graph in this window should look like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-50%2C250%2C-500%2C16000%2C+x%2A%28250-x%29+%29+ ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-50%2C250%2C-500%2C16000%2C+x%2A%28250-x%29+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This confirms that the maximum occurs at x = 125, and the value there for the area is y = about 15,000 or 16,000.  The exact value can be found by substituting x = 125 into the formula A = x(250-x).\r<BR>\n" );
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document.write( "R^2  </SPAN>\n" );
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