document.write( "Question 186499: The sum of 4 times Lottie's age and 7 times Eddie's age is 169. Eddie is one year more than twice as old ad Lottie. Find each of their ages. \n" ); document.write( "

Algebra.Com's Answer #139760 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Let L = Lottie's age now
\n" ); document.write( "Let E = Eddie's age now
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "The sum of 4 times Lottie's age and 7 times Eddie's age is 169.
\n" ); document.write( "4L + 7E = 169
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\n" ); document.write( " Eddie is one year more than twice as old ad Lottie.
\n" ); document.write( "E = 2L + 1
\n" ); document.write( ":
\n" ); document.write( " Find each of their ages.
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\n" ); document.write( "Substitute (2L+1) for E in the 1st equation:
\n" ); document.write( "4L + 7(2L+1) = 169
\n" ); document.write( ":
\n" ); document.write( "4L + 14L + 7 = 169
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\n" ); document.write( "18L = 169 - 7
\n" ); document.write( "L = $\"162%2F18\"$
\n" ); document.write( "L = 9 yrs is Lottie's present age
\n" ); document.write( "then
\n" ); document.write( "E = 2(9) + 1
\n" ); document.write( "E = 19 yrs is Eddie's present age
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\n" ); document.write( "Check solution in the statement,
\n" ); document.write( "\"The sum of 4 times Lottie's age and 7 times Eddie's age is 169.\"
\n" ); document.write( "4(9) + 7(19) = 169, confirms our solution
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