document.write( "Question 26014: Could you please help me with this problem: The excursion boat \"Holiday\" travels 35 km upstream and then back again in 4hours and 48 minutes. If the speed on the \"Holiday\" in still water is 15 km/h, what is the speed of the current? \r
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Algebra.Com's Answer #13976 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! 4 hours and 48 minutes = 4.8hours \n" ); document.write( "Still water speed = 15 \n" ); document.write( "Speed with the current = 15+x \n" ); document.write( "Speed against the current = 15-x \n" ); document.write( "total distance == 35 \n" ); document.write( "Equation: \n" ); document.write( " \n" ); document.write( "35[(15+x)+(15-x)]=4.8[(15+x)(15-x)] SIMPLIFY \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x=2.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the speed of the current is 2.5km/h. \n" ); document.write( "Paul. \n" ); document.write( " \n" ); document.write( " |