document.write( "Question 186471: 4^2x+1=64\r
\n" ); document.write( "\n" ); document.write( " 4^log X=8
\n" ); document.write( "
\n" ); document.write( " e^x+1=.05\r
\n" ); document.write( "\n" ); document.write( " Please help me solve these problems. Thank you!
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Algebra.Com's Answer #139742 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
4^(2x+1) = 64
\n" ); document.write( "4^(2x+1) = 4^3
\n" ); document.write( "2x+1 = 3
\n" ); document.write( "2x = 2
\n" ); document.write( "x = 1
\n" ); document.write( "------------------------\r
\n" ); document.write( "\n" ); document.write( "4^log X=8
\n" ); document.write( "2^(2logx) = 2^3
\n" ); document.write( "2logx = 3
\n" ); document.write( "logx = 3/2
\n" ); document.write( "x = 10^(3/2)
\n" ); document.write( "x = 31.6228
\n" ); document.write( "-------------------------\r
\n" ); document.write( "\n" ); document.write( "e^(x+1)=.05
\n" ); document.write( "Take the natural log of both sides to get:
\n" ); document.write( "x+1 = ln(0.5)
\n" ); document.write( "x+1 = -2.9957
\n" ); document.write( "x = -3.9957
\n" ); document.write( "----------------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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