document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26026>Question 26026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you solve this please?<BR>\n" );
document.write( "2x+2y=2<BR>\n" );
document.write( "3x+y=1<BR>\n" );
document.write( "Can you use the substituion Method?<BR>\n" );
document.write( "I have NO idea. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13974 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the 2nd equation as follows:  y=-3x+1<BR>\n" );
document.write( "Substitute that into the 1st equation to get:<BR>\n" );
document.write( "  2x+2(-3x+1)=2<BR>\n" );
document.write( "Divide thru by \"2\" to get:<BR>\n" );
document.write( "  x+(-3x+1)=1<BR>\n" );
document.write( "    -2x+1 = 1<BR>\n" );
document.write( "     -2x=0<BR>\n" );
document.write( "       x=0<BR>\n" );
document.write( "Put that value of \"x\" into either of the original equations, as follows:<BR>\n" );
document.write( "0+2y=2<BR>\n" );
document.write( "   y=1<BR>\n" );
document.write( "Check those values for \"x\" and \"y\" in the other original equations:<BR>\n" );
document.write( "3(0)+1=1<BR>\n" );
document.write( "     1=1<BR>\n" );
document.write( "So the solution for the system is x=0, y=1.\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "    </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );