document.write( "Question 186409: y=3x and x + y=2\r
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\n" ); document.write( "\n" ); document.write( "answer: 1/2, 3/2\r
\n" ); document.write( "\n" ); document.write( "wanted to know how my book got these fractions as answer need full break down
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Algebra.Com's Answer #139711 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(1) \"y+=+3x\" and
\n" ); document.write( "(2) \"x+%2B+y+=+2\"
\n" ); document.write( "There are 2 equations and 2 unknowns. Whenever the
\n" ); document.write( "number of unknowns matches the number of equations,
\n" ); document.write( "then a solution is possible.
\n" ); document.write( "First, subtract \"y\" from both sides of (1)
\n" ); document.write( "(1) \"y+=+3x\"
\n" ); document.write( "(1) \"0+=+3x+-+y\"
\n" ); document.write( "Now simply add (1) and (2)
\n" ); document.write( "(1) \"3x+-+y+=+0\"
\n" ); document.write( "(2) \"x+%2B+y+=+2\"
\n" ); document.write( "(3) \"4x+=+2\"
\n" ); document.write( "(3) \"x+=+1%2F2\"
\n" ); document.write( "To find \"y\", substitute \"x+=+1%2F2\" in (1)
\n" ); document.write( "(1) \"y+=+3x\"
\n" ); document.write( "(1) \"y+=+3%2A%281%2F2%29\"
\n" ); document.write( "(1) \"y+=+3%2F2\"
\n" ); document.write( "The solution is \"x+=+1%2F2\" and \"y+=+3%2F2\"
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