document.write( "Question 186415: a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $90 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the $20 coffee should be used? \n" ); document.write( "

Algebra.Com's Answer #139704 by stanbon(75887) $\"\"$ $\"About$

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a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $90 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the $20 coffee should be used?
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\n" ); document.write( "Equation:
\n" ); document.write( "value + value = value
\n" ); document.write( "20x + 90*80 = 60(x+80)
\n" ); document.write( "20x = 90*80 = 60x + 60*80
\n" ); document.write( "-40x = -30*80
\n" ); document.write( "x = 30*2
\n" ); document.write( "x = 60 lbs (amt. of $20 coffee needed in the mixtue
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "

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