document.write( "Question 186344: soybean meal is 18% protien; cornmeal is 9% protien. How many pounds of each should be mixed together in order to get 390-lb mixture that is 11% protien?
\n" ); document.write( "how many pounds of the cornmeal should be in the mixtue?
\n" ); document.write( "how many pounds of the soybean meal should be in the mixture?
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Algebra.Com's Answer #139699 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.18x+.09(390-x)=.11*390
\n" ); document.write( ".18x+35.1-.09=42.9
\n" ); document.write( ".09x=42.9-35.1
\n" ); document.write( ".09x=7.8
\n" ); document.write( "x=7.8/.09
\n" ); document.write( "x=86.667 lbs. of soybean meal is used.
\n" ); document.write( "390-86.667=303.333 lbs. of cornmeal is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".18*86.667+.09*303.333=.11*390
\n" ); document.write( "15.60+27.3=42.9
\n" ); document.write( "42.9=42.9
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