document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186372>Question 186372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One train leaves a station heading west. Two hours later a second train leaves the same station heading east. The second train is traveling 15 mi/h fast than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate of which each train is traveling </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139698 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rt=d<BR>\n" );
document.write( "r(6+2)+(r+15)6=580<BR>\n" );
document.write( "r*8+6r+90=580<BR>\n" );
document.write( "8r+6r=580-90<BR>\n" );
document.write( "14r=490<BR>\n" );
document.write( "r=490/14<BR>\n" );
document.write( "r=35 mph. is the speed of the slower train.<BR>\n" );
document.write( "35+15=50 mph. is the speed of the faster train.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "35*8+50*6=580<BR>\n" );
document.write( "280+300=580<BR>\n" );
document.write( "580=580 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );