document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186362>Question 186362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sove each system by substitution method.  I do not understand this at all, can someone help with explanations, Thanks.<BR>\n" );
document.write( "x+3y=2<BR>\n" );
document.write( "-x+y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139696 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+3y=2<BR>\n" );
document.write( "x=2-3y<BR>\n" );
document.write( "Now replace x in the second equation with (2-3y)<BR>\n" );
document.write( "-x+y=1<BR>\n" );
document.write( "-(2-3y)+y=1<BR>\n" );
document.write( "-2+3y+y=1<BR>\n" );
document.write( "4y=1+2<BR>\n" );
document.write( "4y=3<BR>\n" );
document.write( "y=3/4 ans.<BR>\n" );
document.write( "x=2-3*3/4<BR>\n" );
document.write( "x=2-9/4<BR>\n" );
document.write( "x=(2*4-9)/4<BR>\n" );
document.write( "x=(8-9)/4<BR>\n" );
document.write( "x=-1/4 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "1(-1/4)+3/4==1<BR>\n" );
document.write( "1/4+3/4=1<BR>\n" );
document.write( "1=1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );