document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186360>Question 186360</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 15% acid and a second that is 25% acid. How many liters of each should be mixed together to get 100L that is 18% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139689 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .25x+.15(100-x)=.18*100<BR>\n" );
document.write( ".25x+15-.15x=18<BR>\n" );
document.write( ".10x=18-15<BR>\n" );
document.write( ".10x=3<BR>\n" );
document.write( "x=3/.10<BR>\n" );
document.write( "x=30 L of 25% acid is used.<BR>\n" );
document.write( "100-30=70 L of 15% acid is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".25*30+.15*70=.18*100<BR>\n" );
document.write( "7.5+10.5=18<BR>\n" );
document.write( "18=18 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );