document.write( "Question 186368: I'm needing some help with the following problem: Factor each completely. Some may require several steps.\r
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Algebra.Com's Answer #139679 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3a%5E4-6a%5E3%2B9a%5E2\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"3a%5E2%28a%5E2-2a%2B3%29\" Factor out the GCF \"3a%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "It turns out that the inner trinomial can't be factored any further. So this means that \"3a%5E4-6a%5E3%2B9a%5E2\" factors to \"3a%5E2%28a%5E2-2a%2B3%29\".
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