document.write( "Question 186370: I'm needing some help with the following problem: Factor each completely. Some may require several steps.\r
\n" ); document.write( "\n" ); document.write( "y^3-8z^3\r
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Algebra.Com's Answer #139678 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"y%5E3-8z%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%29%5E3-%282z%29%5E3\" Rewrite \"y%5E3\" as \"%28y%29%5E3\". Rewrite \"8z%5E3\" as \"%282z%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28y-2z%29%28%28y%29%5E2%2B%28y%29%282z%29%2B%282z%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y-2z%29%28y%5E2%2B2yz%2B4z%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"y%5E3-8z%5E3\" factors to \"%28y-2z%29%28y%5E2%2B2yz%2B4z%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"y%5E3-8z%5E3=%28y-2z%29%28y%5E2%2B2yz%2B4z%5E2%29\"
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