document.write( "Question 186309: Paul's age is six less than twice Lucien's age. Two years ago, the sum of their age was 29. How old is Lucien? \n" ); document.write( "
Algebra.Com's Answer #139666 by feliz1965(151)![]() ![]() ![]() You can put this solution on YOUR website! Paul's age now = 2x - 6\r \n" ); document.write( "\n" ); document.write( "Lucien's age now = x\r \n" ); document.write( "\n" ); document.write( "Paul's age 2 years ago = (2x - 6) - 2\r \n" ); document.write( "\n" ); document.write( "Lucien's age 2 years ago = x - 2\r \n" ); document.write( "\n" ); document.write( "(2x - 6) - 2 + x - 2 = 29\r \n" ); document.write( "\n" ); document.write( "3x - 10 = 29\r \n" ); document.write( "\n" ); document.write( "3x = 10 + 29\r \n" ); document.write( "\n" ); document.write( "3x = 39\r \n" ); document.write( "\n" ); document.write( "x = 39/3\r \n" ); document.write( "\n" ); document.write( "x = 13\r \n" ); document.write( "\n" ); document.write( "Lucien is 13 years old.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |