document.write( "Question 186315: PLEASE HELP ME :) I did not know which topic to select for these questions :(\r
\n" );
document.write( "\n" );
document.write( "1) Find the slope of a line tangent to the curve of y= square root(3-8x)^1/3 at(-3,3). Use the derivative evaluation feature of a graphing calculator to check result.\r
\n" );
document.write( "\n" );
document.write( "2)The amount n (in g) of a compound formed during a chemical change is n=8t/[(2t^2)+3] , where t is the time (in s). Find dn/dt (derivative -I think) for t=4.0s. What is the meaning of the result???\r
\n" );
document.write( "\n" );
document.write( "3) Find the SECOND derivative of the function: y=square root 1-8x ??? \n" );
document.write( "
Algebra.Com's Answer #139656 by stanbon(75887) ![]() You can put this solution on YOUR website! 1) Find the slope of a line tangent to the curve of y= square root(3-8x)^1/3 at(-3,3). Use the derivative evaluation feature of a graphing calculator to check result. \n" ); document.write( "------------- \n" ); document.write( "y' = (1/2)(3-8x)^(-1/2))*(1/3)(3-8x)^(-2/3)*(-8) \n" ); document.write( "------------------------------------------------- \n" ); document.write( "y'(-3) = (1/2)(3+24)^(-1/2))*(1/3)(27)^(-2/3)*-8 \n" ); document.write( "etc. \n" ); document.write( "=======================================================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "2)The amount n (in g) of a compound formed during a chemical change is n=8t/[(2t^2)+3] , were t is the time (in s). Find dn/dt (derivative -I think) for t=4.0s. What is the meaning of the result??? \n" ); document.write( "---- \n" ); document.write( "dn/dt = [[2t^2+3][8] - [8t][4t]}/ [2t^2+3]^2 \n" ); document.write( "---- \n" ); document.write( "dn/dt is the rate at which n changes per t seconds \n" ); document.write( "------------------------------------------------------ \n" ); document.write( " \n" ); document.write( "3) Find the SECOND derivative of the function: y=square root (1-8x) ??? \n" ); document.write( "y' = (1/2)[(1-8x)^(-1/2)] \n" ); document.write( "= -4[(1-8x)^(-1/2)] \n" ); document.write( "============================= \n" ); document.write( "y'' = 4{(-1/2)(1-8x)^(-3/2)} \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |