document.write( "Question 186279: could someone explain to me how i should siplify sqare roots as such;\r
\n" ); document.write( "\n" ); document.write( "2sqrt(3)+sqrt(27)-sqrt(1/3)\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "sqrt(1/2)*(sqrt(8)+sqrt(2))\r
\n" ); document.write( "\n" ); document.write( "or \r
\n" ); document.write( "\n" ); document.write( "sqrt(18)-sqrt(3)over sqrt(6)\r
\n" ); document.write( "\n" ); document.write( "and the last thing i need help in would be; sqrt(a)+sqrt(b) over sqrt(a)-sqrt(b)
\n" ); document.write( "i totally suck when it comes to things like sqrt =(
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Algebra.Com's Answer #139647 by Alan3354(69443)\"\" \"About 
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could someone explain to me how i should siplify sqare roots as such;
\n" ); document.write( "2sqrt(3)+sqrt(27)-sqrt(1/3)
\n" ); document.write( "=2sqrt(3) + 3sqrt(3) - sqrt(1/2)
\n" ); document.write( "see that? sqrt(27) = sqrt(3*9) = sqrt(9)*sqrt(3) = 3sqrt(3)
\n" ); document.write( "-------------
\n" ); document.write( "Then, sqrt(1/3)= sqrt(3/9) = sqrt(3)/sqrt(9) = sqrt(3)/3 right?
\n" ); document.write( "so it's 2sqrt(3) +3sqrt(3) - (1/3) sqrt(3)
\n" ); document.write( "= (5 - 1/3)sqrt(3)
\n" ); document.write( "= 14sqrt(3)/3
\n" ); document.write( "---------------
\n" ); document.write( "or
\n" ); document.write( "sqrt(1/2)*(sqrt(8)+sqrt(2))
\n" ); document.write( "Multiply the sqrt(1/2) thru
\n" ); document.write( "=sqrt(1/2)*sqrt(8) + sqrt(1/2)*sqrt(2)
\n" ); document.write( "=sqrt((1/2)*8) + sqrt((1/2)*2)
\n" ); document.write( "=sqrt(4) + sqrt(1)
\n" ); document.write( "= 2+1
\n" ); document.write( "=3
\n" ); document.write( "------------
\n" ); document.write( "or
\n" ); document.write( "sqrt(18)-sqrt(3)over sqrt(6)
\n" ); document.write( "Divide each term of the NUM
\n" ); document.write( "=sqrt(18/6) - sqrt(3/6)
\n" ); document.write( "=sqrt(3) - sqrt(1/2)
\n" ); document.write( "=sqrt(3) - sqrt(2/4)
\n" ); document.write( "=sqrt(3) - sqrt(2)/2
\n" ); document.write( "-----------------
\n" ); document.write( "and the last thing i need help in would be;
\n" ); document.write( "sqrt(a)+sqrt(b) over sqrt(a)-sqrt(b)
\n" ); document.write( "The thing to do with these is to multiply thru by the conjugate of the DEN
\n" ); document.write( "The conjugate of sqrt(a)-sqrt(b) is sqrt(a)+sqrt(b). The same 2 terms with a different sign (+ instead of -).
\n" ); document.write( "=(sqrt(a)+sqrt(b))*(sqrt(a)+sqrt(b))/(sqrt(a)-sqrt(b))*(sqrt(a)-sqrt(b))
\n" ); document.write( "It can get messy.
\n" ); document.write( "=(a + 2sqrt(ab) + b)/(a-b)
\n" ); document.write( "------------------
\n" ); document.write( "email me with any questions via the thank you note.
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