document.write( "Question 186279: could someone explain to me how i should siplify sqare roots as such;\r
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document.write( "2sqrt(3)+sqrt(27)-sqrt(1/3)\r
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document.write( "or\r
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document.write( "sqrt(1/2)*(sqrt(8)+sqrt(2))\r
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document.write( "or \r
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document.write( "sqrt(18)-sqrt(3)over sqrt(6)\r
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document.write( "and the last thing i need help in would be; sqrt(a)+sqrt(b) over sqrt(a)-sqrt(b)
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document.write( "i totally suck when it comes to things like sqrt =( \n" );
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Algebra.Com's Answer #139647 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! could someone explain to me how i should siplify sqare roots as such; \n" ); document.write( "2sqrt(3)+sqrt(27)-sqrt(1/3) \n" ); document.write( "=2sqrt(3) + 3sqrt(3) - sqrt(1/2) \n" ); document.write( "see that? sqrt(27) = sqrt(3*9) = sqrt(9)*sqrt(3) = 3sqrt(3) \n" ); document.write( "------------- \n" ); document.write( "Then, sqrt(1/3)= sqrt(3/9) = sqrt(3)/sqrt(9) = sqrt(3)/3 right? \n" ); document.write( "so it's 2sqrt(3) +3sqrt(3) - (1/3) sqrt(3) \n" ); document.write( "= (5 - 1/3)sqrt(3) \n" ); document.write( "= 14sqrt(3)/3 \n" ); document.write( "--------------- \n" ); document.write( "or \n" ); document.write( "sqrt(1/2)*(sqrt(8)+sqrt(2)) \n" ); document.write( "Multiply the sqrt(1/2) thru \n" ); document.write( "=sqrt(1/2)*sqrt(8) + sqrt(1/2)*sqrt(2) \n" ); document.write( "=sqrt((1/2)*8) + sqrt((1/2)*2) \n" ); document.write( "=sqrt(4) + sqrt(1) \n" ); document.write( "= 2+1 \n" ); document.write( "=3 \n" ); document.write( "------------ \n" ); document.write( "or \n" ); document.write( "sqrt(18)-sqrt(3)over sqrt(6) \n" ); document.write( "Divide each term of the NUM \n" ); document.write( "=sqrt(18/6) - sqrt(3/6) \n" ); document.write( "=sqrt(3) - sqrt(1/2) \n" ); document.write( "=sqrt(3) - sqrt(2/4) \n" ); document.write( "=sqrt(3) - sqrt(2)/2 \n" ); document.write( "----------------- \n" ); document.write( "and the last thing i need help in would be; \n" ); document.write( "sqrt(a)+sqrt(b) over sqrt(a)-sqrt(b) \n" ); document.write( "The thing to do with these is to multiply thru by the conjugate of the DEN \n" ); document.write( "The conjugate of sqrt(a)-sqrt(b) is sqrt(a)+sqrt(b). The same 2 terms with a different sign (+ instead of -). \n" ); document.write( "=(sqrt(a)+sqrt(b))*(sqrt(a)+sqrt(b))/(sqrt(a)-sqrt(b))*(sqrt(a)-sqrt(b)) \n" ); document.write( "It can get messy. \n" ); document.write( "=(a + 2sqrt(ab) + b)/(a-b) \n" ); document.write( "------------------ \n" ); document.write( "email me with any questions via the thank you note. \n" ); document.write( " |