document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26002>Question 26002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is y = 1/2x + 1 and \"x\" is -4.  How do we figure out what -y is on the graph?  Please help!!!!  Thank you.\r<BR>\n" );
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document.write( "y = 1/2(-4) + 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13963 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, you're almost there!<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%281%2F2%29%28-4%29+%2B+1 ALIGN=MIDDLE  ALT=\"y+=+%281%2F2%29%28-4%29+%2B+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-2+%2B+1 ALIGN=MIDDLE  ALT=\"y+=+-2+%2B+1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-1 ALIGN=MIDDLE  ALT=\"y+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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