document.write( "Question 186239: A 4m by 6m rug covers half the floor area of a room and leaves a uniform strip of base floor around the edges. What are the dimensions of the room? \n" ); document.write( "
Algebra.Com's Answer #139619 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 4*6=24 m^2 is the area of the rug. \n" ); document.write( "(4+2x)(6+2x)=2*24 \n" ); document.write( "24+12x+4x+4x^2=48 \n" ); document.write( "8x+12x+24-48=0 \n" ); document.write( "8x+12x-24=0 \n" ); document.write( "4(2x^2+3-6)=0 \n" ); document.write( "4(2x-2)(x+3)=0 \n" ); document.write( "2x-2=0 \n" ); document.write( "2x=2 \n" ); document.write( "x=1 m. is the width of the edge. \n" ); document.write( "Proof: \n" ); document.write( "(4+2*1)(6+2*1)=2*24 \n" ); document.write( "(4+2)(6+2)=48 \n" ); document.write( "6*8=48 \n" ); document.write( "48=48\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |