document.write( "Question 186239: A 4m by 6m rug covers half the floor area of a room and leaves a uniform strip of base floor around the edges. What are the dimensions of the room? \n" ); document.write( "
Algebra.Com's Answer #139619 by checkley77(12844)\"\" \"About 
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4*6=24 m^2 is the area of the rug.
\n" ); document.write( "(4+2x)(6+2x)=2*24
\n" ); document.write( "24+12x+4x+4x^2=48
\n" ); document.write( "8x+12x+24-48=0
\n" ); document.write( "8x+12x-24=0
\n" ); document.write( "4(2x^2+3-6)=0
\n" ); document.write( "4(2x-2)(x+3)=0
\n" ); document.write( "2x-2=0
\n" ); document.write( "2x=2
\n" ); document.write( "x=1 m. is the width of the edge.
\n" ); document.write( "Proof:
\n" ); document.write( "(4+2*1)(6+2*1)=2*24
\n" ); document.write( "(4+2)(6+2)=48
\n" ); document.write( "6*8=48
\n" ); document.write( "48=48\r
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