document.write( "Question 186229: Find two consecutive odd integers such that the square of the first added to 3 times the second is 24. \n" ); document.write( "
Algebra.Com's Answer #139610 by checkley77(12844)\"\" \"About 
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Let x & (x+2) be the 2 integers.
\n" ); document.write( "x^2+3(x+2)=24
\n" ); document.write( "x^2+3x+6=24
\n" ); document.write( "x^2+3x+6-24=0
\n" ); document.write( "x^2+3x-18=0
\n" ); document.write( "(x+6)(x-3)=0
\n" ); document.write( "x-3=0
\n" ); document.write( "x=3 ans. for the smaller integer.
\n" ); document.write( "3+2=5 ans. for the larger integer.
\n" ); document.write( "Proof:
\n" ); document.write( "3^2+3*5=24
\n" ); document.write( "9+15=24
\n" ); document.write( "24=24
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