document.write( "Question 186229: Find two consecutive odd integers such that the square of the first added to 3 times the second is 24. \n" ); document.write( "
Algebra.Com's Answer #139610 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Let x & (x+2) be the 2 integers. \n" ); document.write( "x^2+3(x+2)=24 \n" ); document.write( "x^2+3x+6=24 \n" ); document.write( "x^2+3x+6-24=0 \n" ); document.write( "x^2+3x-18=0 \n" ); document.write( "(x+6)(x-3)=0 \n" ); document.write( "x-3=0 \n" ); document.write( "x=3 ans. for the smaller integer. \n" ); document.write( "3+2=5 ans. for the larger integer. \n" ); document.write( "Proof: \n" ); document.write( "3^2+3*5=24 \n" ); document.write( "9+15=24 \n" ); document.write( "24=24 \n" ); document.write( " \n" ); document.write( " |