document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186238>Question 186238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right triangle is 14 meters longers than the other leg. The hypotenuse is 26 meters long. Find the length of each leg. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139604 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2+(X+14)^2=26^2<BR>\n" );
document.write( "X^2+X^2+28X+196=676<BR>\n" );
document.write( "2X^2+28X+196-676=0<BR>\n" );
document.write( "2X^2+28X-480=0<BR>\n" );
document.write( "2(X^2+14X-240)=0<BR>\n" );
document.write( "2(X+24)(X-10)=0<BR>\n" );
document.write( "X-10=0<BR>\n" );
document.write( "X=10 M. ANS. FOR THE SHORTER LEG.<BR>\n" );
document.write( "10=14=24 M. ANS. FOR THE LONGER LEG.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "10^2+24^2=26^2<BR>\n" );
document.write( "100+576=676<BR>\n" );
document.write( "676=676<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );