document.write( "Question 186175: The sum of two consecutive integers 111. Three times the larger integer less two times the smaller integer is 58. Find the value of the smaller integer \n" ); document.write( "

Algebra.Com's Answer #139586 by checkley77(12844) $\"\"$ $\"About$

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x+(x+1)=111 or 2x+1=111 or 2x=111-1 or 2x=110 or x=110/2 or x=55 is the smaller integer.
\n" ); document.write( "3(x+1)-2x=58
\n" ); document.write( "3(55+1)-2*55=58
\n" ); document.write( "3*56-110=58
\n" ); document.write( "168-110=58
\n" ); document.write( "58=58 \n" ); document.write( "

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