document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186124>Question 186124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log3 81= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139574 by </B><A HREF=/tutors/aboutme.mpl?userid=feliz1965><B>feliz1965(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=feliz1965><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log_3 81 = x\r<BR>\n" );
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document.write( "We can write this log expression in exponential form this way: 3^(x) = 81.\r<BR>\n" );
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document.write( "So, 3 becomes the base, x becomes the exponent and 81 crosses the equal sign and is isolated.\r<BR>\n" );
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document.write( "Feliz\r<BR>\n" );
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document.write( "P.S. If you need to find the answer for x, ask yourself:\r<BR>\n" );
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document.write( "what number must 3 be raised to in order to get 81?\r<BR>\n" );
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document.write( "The obvious answer is x = 4.  \r<BR>\n" );
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document.write( "Look: 3 x 3 x 3 x 3 = 81\r<BR>\n" );
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document.write( "So, log_3 81 = 4\r<BR>\n" );
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