document.write( "Question 185134: SUSAN WANTS TO HAVE BUSINESS CARDS PRINTED. ONE STYLE WILL COST $25 PLUS 2CENTS PER CARD. ANOTHER STYLE WILL COST $10 PLUS 5CENTS FOR EVERY CARD.
\n" ); document.write( "FOR HOW MANY CARDS WILL THE COST BE THE SAME FOR BOTH STYLES? \n" ); document.write( "

Algebra.Com's Answer #139518 by swiemers(10) $\"\"$ $\"About$

You can put this solution on YOUR website!
To do this, you need to make them equal each other in an equation. Therefore, we could say:
\n" ); document.write( "25 + .02x = 10 + .05x
\n" ); document.write( "where x = the number of cards to be printed. They want to know when they are the same, so you set them equal to each other. Then you need to solve for x.
\n" ); document.write( "25 + .02x = 10 + .05x
\n" ); document.write( "First combine the x variables by subtracting the .02x and moving it over to the .05x and you get:
\n" ); document.write( "25 = 10 + .03x
\n" ); document.write( "Then you want to isolate the x variable so we have to move the 10 over. We do so by subtracting it from both sides and we get:
\n" ); document.write( "15 = .03x
\n" ); document.write( "Then you divide each side by .03 to get x by itself and you get:
\n" ); document.write( "x = 500
\n" ); document.write( "Therefore, the cost will be the same at 500 cards. \r
\n" ); document.write( "\n" ); document.write( "Hope this helps! Good luck! Sandy :-) \n" ); document.write( "

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