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You can put this solution on YOUR website!
I'm assuming you are supposed to factor or simply the expressions, so that's how I'll solve them.
\n" ); document.write( "1. 5x^3y - 125xy
\n" ); document.write( "Factor out 5xy and get:
\n" ); document.write( "5xy(x^2 - 25)
\n" ); document.write( "Then you can factor the parentheses as the difference of two squares into:
\n" ); document.write( "5xy(x - 5)(x + 5)\r
\n" ); document.write( "\n" ); document.write( "2. 2m^3 + 16
\n" ); document.write( "Factor out a 2 and get:
\n" ); document.write( "2(x^3 + 8)
\n" ); document.write( "Then use the sum of two cubes rule to factor the parentheses into:
\n" ); document.write( "2(x + 2) (x^2 - 2x + 4)\r
\n" ); document.write( "\n" ); document.write( "3. 2x^3 + 6x^2 - 3x - 9
\n" ); document.write( "This one we need to factor by grouping. First, group the first two terms together:
\n" ); document.write( "2x^3 + 6x^2
\n" ); document.write( "We can factor out 2x^2 and get:
\n" ); document.write( "2x^2(x + 3)
\n" ); document.write( "Second, group the second two terms together:
\n" ); document.write( "-3x - 9
\n" ); document.write( "We can factor out a -3 and get:
\n" ); document.write( "-3(x + 3)
\n" ); document.write( "So all of our factored problem so far is:
\n" ); document.write( "2x^2(x + 3) -3(x + 3)
\n" ); document.write( "When you are factoring by grouping, you rewrite this as two parentheses. The first is what's inside the parentheses - as long as it is THE SAME. The second parentheses is what is left over. So, it would become:
\n" ); document.write( "(x + 3) (2x^2 - 3)\r
\n" ); document.write( "\n" ); document.write( "Hope this helps! Good luck! Sandy :-) \n" ); document.write( "