document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=186008>Question 186008</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073534961/algebrahomeworkh>Elementary Statistics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 40.)  A newspaper advertises 5 different movies, 3 plays, and 2 baseball games for the weekend. If a couple selects 3 activities, find the probability that they attend 2 plays and 1 movie.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139496 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A newspaper advertises 5 different movies, 3 plays, and 2 baseball games for the weekend. If a couple selects 3 activities, find the probability that they attend 2 plays and 1 movie. <BR>\n" );
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document.write( "# of ways to pick 2 plays: 3C2 = 3 ways<BR>\n" );
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document.write( "# of ways to pick 1 movie: 5C1 = 5 ways<BR>\n" );
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document.write( "total number of ways to pick 2plays and 1 movie = 3*15 = 45 ways<BR>\n" );
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document.write( "# of ways to select 3 activiies without restriction: 10C3 = (10*9*8)/(1*2*3)<BR>\n" );
document.write( "= 120<BR>\n" );
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document.write( "Therefore the prob (3 plays and 1 movie) = 45/120 = 3/8\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );