document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185005>Question 185005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 48. Three times the smaller number is the same as 32 more than the larger. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139465 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two numbers be X and Y.\r<BR>\n" );
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document.write( "We know X + Y = 48\r<BR>\n" );
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document.write( "We are told that three times the smaller is 32 more than the bigger, so by taking 32 from three times the smaller we have the bigger. This gives 3X – 32 = Y\r<BR>\n" );
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document.write( "Substitute Y = 3X – 32 into X + Y = 48 gives X + 3X – 32 = 48<BR>\n" );
document.write( "4X – 32 = 48<BR>\n" );
document.write( "4X = 80<BR>\n" );
document.write( "X = 20, Y = 28\r<BR>\n" );
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document.write( "Check: 3 x 20 (=60) is 32 more than 28. Correct. </SPAN>\n" );
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