document.write( "Question 185868: Hi ... I was hoping someone can help me with this problem.
\n" ); document.write( "The population of Springfield is decreasing at a rate of 250 people per year. Find the data that is missing from the chart.
\n" ); document.write( "Year Population
\n" ); document.write( "? 8400
\n" ); document.write( "2002 8150
\n" ); document.write( "2008 ?
\n" ); document.write( "? 5900
\n" ); document.write( "? 4900
\n" ); document.write( "Thanks so much!! \n" ); document.write( "

Algebra.Com's Answer #139461 by edjones(8007) $\"\"$ $\"About$

You can put this solution on YOUR website!
Year Population
\n" ); document.write( "2001 8400
\n" ); document.write( "2002 8150
\n" ); document.write( "2008 6650
\n" ); document.write( "2011 5900
\n" ); document.write( "2015 4900
\n" ); document.write( ".
\n" ); document.write( "2008-2002=6
\n" ); document.write( "6*-250=-1500
\n" ); document.write( "8150-1500=6650
\n" ); document.write( ".
\n" ); document.write( "6650-5900=750
\n" ); document.write( "750/250=32008+3=2011
\n" ); document.write( ".
\n" ); document.write( "5900-4900=1000
\n" ); document.write( "1000/250=4
\n" ); document.write( "2011+4=2015
\n" ); document.write( ".
\n" ); document.write( "8400-8150=250
\n" ); document.write( "250/250=1
\n" ); document.write( "2002-1=2001
\n" ); document.write( ".
\n" ); document.write( "Ed
\n" ); document.write( " \n" ); document.write( "

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