document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185942>Question 185942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lina is 1\3 times as old as anita. six years ago she was 1\9 as old as anita .what is the present age of anita? of Lina?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139456 by </B><A HREF=/tutors/aboutme.mpl?userid=feliz1965><B>feliz1965(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=feliz1965><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lina's present age = x/3\r<BR>\n" );
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document.write( "Anita's present age = x\r<BR>\n" );
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document.write( "Lina's age 6 years ago = (x/3) - 6\r<BR>\n" );
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document.write( "Then (x/3) - 6 = (x/9)....This equation came from the words \"Six years ago, she was 1\9 as old as Anita.\" \r<BR>\n" );
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document.write( "(x/3) - 6 = (x/9)....We now mutiply both sides of the equation by 9 to remove the fractions.  \r<BR>\n" );
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document.write( "Afterward, we get this:\r<BR>\n" );
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document.write( "3x - 54 = x\r<BR>\n" );
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document.write( "3x - x = 54\r<BR>\n" );
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document.write( "2x = 54\r<BR>\n" );
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document.write( "x = 27\r<BR>\n" );
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document.write( "Anita is 27 years old.  Lina is 1/3 times 27 or 9 years old.\r<BR>\n" );
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