document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185942>Question 185942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> lina is 1\3 times as old as anita. six years ago she was 1\9 as old as anita .what is the present age of anita? of Lina?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139455 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let L=Lina's present age and a=anita's<BR>\n" );
document.write( "L=a/3<BR>\n" );
document.write( "L-6=(a-6)/9<BR>\n" );
document.write( "(a/3)-6=(a-6)/9 substitute a/3 for L.<BR>\n" );
document.write( "(9a/3)-54=a-6 Multiply each side by 9 (LCM) to eliminate fractions.<BR>\n" );
document.write( "3a-54=a-6<BR>\n" );
document.write( "2a=48<BR>\n" );
document.write( "a=24<BR>\n" );
document.write( "L=8<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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