document.write( "Question 185848: Dave Salcedo has $40,000 to invest. He invests part of it at 5%, one-fourth of this amount at 6%, and the rest of the money at 7%. His total annual interest income is $2530. Find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #139434 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Dave Salcedo has $40,000 to invest. He invests part of it at 5%, one-fourth \n" ); document.write( " of this amount at 6%, and the rest of the money at 7%. His total annual \n" ); document.write( " interest income is $2530. Find the amount invested at each rate. \n" ); document.write( ": \n" ); document.write( "We have 3 amts \n" ); document.write( "let x = amt invested at 5% \n" ); document.write( "then \n" ); document.write( ".25x = amt invested at 6% \n" ); document.write( "and \n" ); document.write( "(40000-1.25x) = amt invested at 7% \n" ); document.write( ": \n" ); document.write( ".05x + .06(.25x) + .07(40000-1.25x) = 2530 \n" ); document.write( ": \n" ); document.write( ".05x + .015x + 2800 - .0875x = 2530 \n" ); document.write( ": \n" ); document.write( ".05x + .015x - .0875x = 2530 - 2800 \n" ); document.write( ": \n" ); document.write( "-.0225x = -270 \n" ); document.write( "x = \n" ); document.write( "x = $12000 invested at 5% \n" ); document.write( ": \n" ); document.write( ".25(12000) = $3000 invested at 6% \n" ); document.write( "and \n" ); document.write( "40000 - 12000 - 3000 = $25000 invested at 7% \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check solution by finding the total interest \n" ); document.write( ".05(12000) + .06(3000) + .07(25000) = \n" ); document.write( "600 + 180 + 1750 = 2530, confirms out solutions \n" ); document.write( " |