document.write( "Question 25939: a factory has a weak 1% acid solution and a stronger 25% acid solution. if you need to make 2000ml of 5% acid solution to perform a certain cleaning task, how many liters of each should you use?\r
\n" ); document.write( "\n" ); document.write( "antifreeze a is 15% alcohol. antifreeze b is 10% alcohol. how many liters of each should be mixed in order to get 20 liters of a mixture that is 18% alcohol? \n" ); document.write( "
Algebra.Com's Answer #13940 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
1.
\n" ); document.write( "x+25(2000-x)=5(2000)
\n" ); document.write( "x-25x+50000=10000
\n" ); document.write( "-24x=-40000
\n" ); document.write( "x=1666.7 (rounded)
\n" ); document.write( "2000-1666.7=333.3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, you need to use 1666.7ml of 1% and a 333.3ml of 25%.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2.
\n" ); document.write( "10x+18(20)=15(x+20)
\n" ); document.write( "10x+360=15x+300
\n" ); document.write( "-5x=-60
\n" ); document.write( "x=12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "20-12=8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, about 12L of 15% solution must be added, and about 8L of 10% solution must be added.
\n" ); document.write( "PAUL<>\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );